Question

a body of mass 10kg is moving with a velocity of 15m/s. When a force is applied on it, its velocity becomes 35m/s after 10sec. Calculate the applied force.​

Answer 1

Solution:

Force is defined as the product of mass of the body and acceleration acting on a body.

In terms of formula it can be written as:

• Force = Mass × Acceleration

Acceleration is defined as the rate of change of velocity in a given time interval. The formula for calculating acceleration is given as:

• Acceleration = [tex]\dfrac{v-u}{t} [/tex}

Where (v-u) is the change in velocity and t is the time taken.

According to the question,

Mass of the body is given as 10 kg.

Initial Velocity is 15 m/s and Final Velocity is 35 m/s

Hence the change in velocity is given as:

→ 35 - 15 = 20 m/s

Time interval for the change = 10 seconds

Therefore acceleration is given as;

→ Acceleration = 20 m/s / 10 s = 2 m/s²

Applying the values in the formula for force we get:

→ Force = 10 Kg × 2 m/s²

→ Force = 20 Kg.m/s² = 20 N

Hence the value of the applied force is 20 N.

Answer 2

Answer:

• Mass = 10 kg
• Initial Velocity = 15 m/s
• Final Velocity = 35 m/s
• Time = 10 sec

$\rule{120}{1}$

$\underline{\bigstar\:\textbf{According to the Question :}}$

$:\implies\sf F=ma\\\\\\:\implies\sf Force=Mass \times Acceleration\\\\\\:\implies\sf Force=Mass \times \dfrac{Final\: Velocity- Initial\: Velocity}{Time}\\\\\\:\implies\sf Force=10\:kg \times \dfrac{35\:m/s-15\:m/s}{10\:s}\\\\\\:\implies\sf Force=10\:kg \times \dfrac{20\:m/s}{10\:s}\\\\\\:\implies\sf Force=10\:kg \times 2\:m/s^2\\\\\\:\implies\underline{\boxed{\sf Force=20\:N}}$

⠀

$\therefore\:\underline{\textsf{Hence, Force applied on the body is \textbf{20 N}}}.$