Question

A body of mass 15kg moving with velocity of 10m/s is brought to rest by appying brakes workdone by the brakes is

Answer 1

We know, work done, W = F × s

Where, F is the force applied and s is the distance travelled by the particle.

Also, W = (F/a) × s × a
(dividing and multiplying by a)

where a is deceleration.

We also know,
${v}^{2} = {u}^{2} - 2as \\ \: or \\ 0 = {10}^{2} - 2as \\ or \\ 100 = 2as \\ or \\ as = 50$
and from Newton's Second Law of Motion,
F = ma
where m is the mass of the body.

F/a = m
or, F/a = 15

going back to W = (F/a) × s × a , and putting the values, we get,
W = 15 × 50
= 750 Nm

The answer is 750 Nm.

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