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HOLA !!
HERE'S YOUR FRIEND,
(i) Since AB || CD,
• ang.ABO = ang.OCD (AB|| CD AND BC IS THE TRANSVERSEL)
• ang.BAO = angle.ODC ( AB || CD AND AD IS THE TRANSVERSEL )
• AB = CD ( GIVEN )
THEREFORE BY ASA CRITEREA, THE 2 TRIANGLES ARE CONGRUENT.
(ii) since triangle AOB ≈ triangle COD,
by cpct, OA = OD.
(iii) similarly, by cpct
OB = OC.
I HOPE YOU FIND IT HELPFUL.
YOUR FRIEND
LB.... :-D
HERE'S YOUR FRIEND,
(i) Since AB || CD,
• ang.ABO = ang.OCD (AB|| CD AND BC IS THE TRANSVERSEL)
• ang.BAO = angle.ODC ( AB || CD AND AD IS THE TRANSVERSEL )
• AB = CD ( GIVEN )
THEREFORE BY ASA CRITEREA, THE 2 TRIANGLES ARE CONGRUENT.
(ii) since triangle AOB ≈ triangle COD,
by cpct, OA = OD.
(iii) similarly, by cpct
OB = OC.
I HOPE YOU FIND IT HELPFUL.
YOUR FRIEND
LB.... :-D
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