A body of mass 2 kg is resting on a rough horizontal surface . A force of 20 N ia now applied to it for 10 secs , parallel to the surface . If the coefficient of kinetic friction between the suefaces in contact is 0.2 , calculate- 1)Work done by the applied force in 10 secs. 2)Change in Kinetic energy of the object in 10 secs Take g as 10 m/s²
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Body of mass 2 kg is resting on a rough horizontal surface. The surface is “8N”.
Or even 8 N.unless you let me re-type your homework question. coefficient of friction if a wooden block of mass 1.6 kg resting on a rough horizontal surface and force of 20 N is now applied to it for 10 secs , parallel to the surface.
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Explanation:Body of mass 2 kg is resting on a rough horizontal surface. The surface is “8N”.
Or even 8 N.unless you let me re-type your homework question. coefficient of friction if a wooden block of mass 1.6 kg resting on a rough horizontal surface and force of 20 N is now applied to it for 10 secs , parallel to the surface.
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