Question

the sum of 47 distinct positive integers is 2015 .at most how many of these positive integers are odd

Answer 1

For making the possible difference between largest number and smallest one largest, it is necessary to set the 4 first numbers that is smallest and final number largest.

These positive integers are distinct and 4 first numbers are the 1, 2, 3 and 4.

Sum of numbers is 10 and last number is 90. largest difference is 90 - 1 = 89.