Question

a neon-dioxygen mixture contains 70.6g dioxygen and 167.5g neon. if the pressure of the mixture of gases in the cylinder is 25 bar what are the partial pressures of o2 and ne in the mixture?

Answer 1

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Number of moles of O2 = 70.6/32 = 2.21 mol

Number of moles of neon = 167.5/20 = 8.375 mol

Mol fraction of dioxygen = 2.21/2.21+8.375 = 0.21

Mol fraction of neon = 1- 0.21 = 0.79

Partial pressure of gas = Mol fraction × total pressure

Partial pressure of oxygen = 0.21 × 25 = 5.24 bar

Partial pressure of neon gas = 0.79 × 25 = 19.75 bar

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Answer 2

$\huge\tt \bar{19.75}$