Question

A body of mass 2 kg moving with a velocity of lomps s is besught to
rest in 5 sec calculate the stopping force applied.​

Answer 1

Given :

Mass of the body = 2 kg

Initial velocity = 10 m/s

Final velocity = zero

Time interval = 5 s

To Find :

Magnitude of applied stopping force.

Solution :

❖ As per newton's second law of motion, force is defined as the rate of change of linear momentum.

Mathematically, F = dp / dt

• F denotes force
• dp denotes change in momentum
• dt denotes change in time

We know that momentum is measured as the product of mass and velocity$.$

∴ F = m (v - u) / t

• v denotes final velocity
• u denotes initial velocity
• t denotes time
• m denotes mass

By substituting the given values;

➙ F = 2(0 - 10) / 5

➙ F = 2(-10) / 5

➙ F = -20/5

➙ F = -4 N

[Negative sign shows retarding force]

Answer 2

Answer:

Question

A body of mass 2 kg moving with a velocity of 10m/sec is bought to rest in 5 sec. calculate the stopping force applied.

GIVEN

• Mass= 2 kg
• inital Velocity= 10m/sec
• final velocity= 0 m/sec
• time =5 sec

To find

calculate the stopping force applied.

Solution

According to Newton's second law of motion

${\boxed{ \boxed{ \sf \purple {f = m.a}}}}$

where

• f denotes force
• m denotes mass
• a denotes accleration

and Acceleration is given as :

${\boxed {\boxed{ \sf{a = \frac{v - u}{t} }}}}$

where

• a denotes accleration
• v denotes final velocity
• u denotes inital Velocity
• t denotes time

So..

${ \boxed {\boxed{ \sf \orange{ \to \: f = m (\frac{v - u}{t} )}}}}$

substitute the values in the above formula :

➠ force = 2 (0-10)/5

➠force = 2× (-10)/5

➠force = (-) 4

⇝ here the minus sign represent that the force is applied in the opposite directon of the motion .

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MoRE information!!

✏️Force is an external agent capable of changing the state of rest or motion of a particular body.

✏️Force is a vector quantity...It has both magnitude and direction.

✏️ SI unit of Force is Newton. (N)

✏️Acceleration is the rate of change of velocity.

✏️SI unit of accleration is m/sec²

✏️It is a vector quantity

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