Question

a body of mass 25kg increase its speed from 30m/s to 55m/s in 10 sec find the force acting on the body​

Answer 1

Answer:

• Mass of body (m) = 25 kg

• Change in velocity (∆v) = (55 - 30) m/s

• time interval (t) = 10 s

• A C C E L E R A T I O N :

⇒a = ∆v/t

⇒a = (v - u)/t

⇒a = (55 - 30)/10

⇒a = 25/10

⇒a = 2.5 m/s²

• F O R C E :

⇒F = ma

⇒F = 25 × 2.5

⇒F = 62.5 N

Answer 2

$\large \rm {\underbrace{\underline{Elucidation:-}}}$

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$\dag \rm \red {\underline{Provided\: that:-}}$

➻Mass of the body (m)=25kg

➻Time(t)=10 sec

➻It's speed increases from 30m/s to 55m/s

★In essence,

$\tt \dashrightarrow {v_{1}=30m/s}$

$\tt \dashrightarrow {v_{2}=55m/s}$

➻Change in it's Velocity (∆v)=$\tt {v_{2}-v_{1}}$

$\tt \dashrightarrow {∆v=55m/s-30m/s}$

$\tt \implies \green {∆v=25m/s}$

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$\dag \rm \blue {\underline{To\: be\: determined:-}}$

➻Force acting on the body(F)=?

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$\dag \rm \pink {\underline{It's\: known\: that:-}}$

$\small \tt {\fbox{Force=mass× acceleration}}$

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➻To determine force , acceleration is to be calculated.

★Acceleration:-The rate of change of Velocity with respect to time.

★Unit:- $\tt {m/s^{2}}$

➻By definition,

$\small \tt {Acceleration (a)=\frac{Change \: in\: Velocity}{Time}}$

$\tt \dashrightarrow{Acceleration (a)=\frac{∆v}{t}}$

$\large \tt \dashrightarrow{a=\frac{25}{10}}$

$\tt \implies \green{Acceleration (a)=2.5m/s^{2}}$

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➻As acceleration is determined,we can calculate force

$\tt \dashrightarrow{Force(F)=m× a}$

➻Supplanting the given values,

$\tt \dashrightarrow{F=25kg\times 2.5m/s^{2}}$

$\tt \dashrightarrow{F=62.5kgm/s^{2}}$

$\tt \implies \green {\fbox{Force=62.5N}}$

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$\dag \rm \purple {\underline{Thusforth,}}$

➻The force acting on the body is 62.5 Newtons.

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