A body of mass 5 kg is thrown vertically upwards with speed of 10 m/s. Whst is the kinetic energy when the object thrown. Find its potential energy when it reaches at the highest point also find the maximum height attained by the body.(take g=10m/s^2)
Answers
Answer:
If a concave mirror were thought of as being a slice of a sphere, then there would be a line passing through the center of the sphere and attaching to the mirror in the exact center of the mirror. This line is known as the principal axis.
Explanation:
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Answer:
Maximum height attained by the body is 5 m.
Given:
Mass of the body, M = 5 kg
Speed with which the body travels, u = 10 m/s
Solution:
We have to initially find the Kinetic difference,
The formula for Kinetic difference is,
K.E=\frac{1}{2} \times m \times u^{2}K.E=
2
1
×m×u
2
=\frac{1}{2} \times 5 \times 10^{2}=
2
1
×5×10
2
=\frac{1}{2} \times 5 \times 100=
2
1
×5×100
=5 \times 50=5×50
K.E = 250 \ JK.E=250 J
The, Potential energy of the body is 250 J, when it reaches the highest point.
Loss in K.E = gain in P.E
→ P.E = 250 J
And the formula for potential difference is,
PE =m \times g \times hPE=m×g×h
250=5 \times 10 \times h250=5×10×h
250=50 \times h250=50×h
h=\frac{250}{50}h=
50
250
h = 5 \ mh=5 m