Question

A body of mass 5 kg moving with a velocity 10 m/s collides with another body of the mass 20 kg at, rest and comes to rest. The velocity of the second body due to collision is

Answer 1

Answer:

Explanation:

mass of 1 body=5kg

velocity os 1 body= 10m/s

mass of 2 body=20kg

velocity of 2 body=?

using fourmala

velocity of 2=mass of 1*velocity of 1/mass of 2

velocity of 2=5*10/20

velocity of 2=2.5m/s

Answer 2

Answer:

If a body of mass 5 kg is moving with a velocity of 10 m/s collides with another body of the mass 20 kg at rest and comes to rest. The velocity of the second body due to collision is $2.5m/s$

Explanation:

When a moving body (mass-$m_{1}$, speed-$u_{1}$) collides with a body (mass-$m_{2}$, speed $u_{2}=0$) at rest momentum should be conserved which means the total momentum after the collision is equal to the total momentum before they collide with each other

the momentum of the first body is $m_{1} u_{1}$ and that of the second body is zero because it is stationary.

mass of the first body $m_{1} =5kg$ and speed $u_{1} =10m/s$

so the total momentum before the collision is $m_{1} u_{1} =5*10=50kgm/s$

mass of the second body $m_{2} =20kg$ and let the speed of the second body be $V_{2}$ after the collision

the first body comes to rest after the collision

therefore total momentum after the collision is $m_{2} v_{2} =20*V_{2}$

using momentum conservation we can write

$20*V_{2}=50kgm/s\\V_{2}=2.5m/s$