A body of mass 500 g initially at rest is acted upon by a force which causes it to move a distance of 4 m in 2 seconds. calculate the force.
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Mass = 0.5kg
Initial Velocity = 0m/s
Final Velocity = 2m/s
Acceleration = 2m/sec sq.
Hence, force = m × a = 0.5 × 2 = 1N (Ans)
Initial Velocity = 0m/s
Final Velocity = 2m/s
Acceleration = 2m/sec sq.
Hence, force = m × a = 0.5 × 2 = 1N (Ans)
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Answer:
Explanation:
mass(m)=500g
initial velocity(u)=0m/s
time=2sec
final velocity(v) =displacement /time
v=4/2=2m/s
acceleration(a) = rate of change of velocity
a=2-0/2
a=1ms^-2
force=m×a
f=500×1
f=500gm.m.s^-2
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