a body of mass 5kg moves from(6i^+5j^-3k^)m to (10i^-2j^+k^)m under the action of force of (10i^-3j^+6k^) then work done is
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Explanation:
displacement = (10i-2j+7k) - (6i+5j-3k), = (4i-7j+10k), work done =force. Displacement = (10i-3j+6k). (4i-7j+10k) = 10×4+3×7+6×10 = 40 + 21 +60 = 121 Joules.15-Jun-2017
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