Question

A body of mass 5kg moving with a velocity 10m/s on a rough horizontal surface is stopped after a distance of 10m. then frictional force acting on it is?

Answer 1

Answer:

25 N

Explanation:

We are given that mass of body=5 Kg

Velocity of body=10 m/s

Distance traveled by body=10 m

We have to find the friction force acting on the body

Work done due to friction force=Kinetic energy

$\frac{1}{2}mv^2=\mu mg \times x$

$\frac{1}{2}(10)^2=\mu\times 10\times 10$

$\mu=0.5$

We know that

Friction force=$\mu mg$

Substitute the values then we get

Friction force, $f_k=0.5\times 5\times 10=25 N$

Hence, friction force applied on the body=25 N

Answer 2

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