Question

a body of mass m has its position x at a time t expressed by the equation x= 3t^3/2 + 2t^-1/2. The instantaneous force on the body is proportional to, (a)t^0. (b)t^-1/2. (c)t. (d)t^3/2​

Answer 1

Answer:

Explanation:

x  = 3t^(3/2)  + 2t^(-1/2)

V = dx/dt  = 3 (3/2) t^(1/2)   + 2(-1/2)t^(-3/2)

=> V = (9/2) t^(1/2) - t^(-3/2)

a = dV/dt = d²x/dt²

=> a = (9/2)(1/2)t^(-1/2)  + (3/2)t^(-5/2)

=> a = (9/4)t^(-1/2)   + (3/2)t^(-5/2)

instantaneous force on the body is proportional to (9/4)t^(-1/2)   + (3/2)t^(-5/2)

Answer 2

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Answer:

hope it helps u bro.