a body of mass m has its position x at a time t expressed by the equation x= 3t^3/2 + 2t^-1/2. The instantaneous force on the body is proportional to, (a)t^0. (b)t^-1/2. (c)t. (d)t^3/2
Answers
Answered by
14
Answer:
Explanation:
x = 3t^(3/2) + 2t^(-1/2)
V = dx/dt = 3 (3/2) t^(1/2) + 2(-1/2)t^(-3/2)
=> V = (9/2) t^(1/2) - t^(-3/2)
a = dV/dt = d²x/dt²
=> a = (9/2)(1/2)t^(-1/2) + (3/2)t^(-5/2)
=> a = (9/4)t^(-1/2) + (3/2)t^(-5/2)
instantaneous force on the body is proportional to (9/4)t^(-1/2) + (3/2)t^(-5/2)
Answered by
2
.
.
.
.
Answer:
hope it helps u bro.
Attachments:

Similar questions