If A and B can do a work in 18 days
B and C can do it in 24 days
A and C can do it in 26 days
In how many days will a b and C will finish it together and separately
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Answer:
A,B,C's one day work=1 /A,I/B, 1/C
1/A +1/B=1/18
1/B +1/C=1/24
1/C+1/A=1/26
Total 2 (1/A+1/B +1/C) =
1/18 +1/24 +1/26=(52+39+36) / 936=127 / 936
1/A+1/B+1/C= (127 / 936) /2 =
127 / 1872
= 14.7 days (ie, 1872/127)
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