a body of mass m is projected with Initial speed u at an angle theta with the horizontal. the change in momentum of body after time t is?answer with full explanation
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as we know that a projectile motion is a combination to horizontal and verticle motion.The vetical component of intial velocity ‘u’ always remains constant ,i.e. in this case ,ux=ucoso, throughout the motion.So change in momentum in horizonal direction is 0(zero).
Now analysing the vertical direction motion we know intial velocity in vertical direction uy=usino.
After time t,vy=usino-gt,(using eq. of motion ,v=u+at)
Thus, Change in momentum in vertical direction =m.vy-m.uy
=m.(usino-gt)-(m.usino)
=-mgt
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