A body possessing an initial velocity of 2 ms- 1 covers a distance of 24 m during the sixth second of its motion calculate the acceleration of the body assuming it to be constant
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given:
u=2ms-1
s=24m
t=6s
a=?
s=ut+1/2at²
24=2*6+1/2*a*36
24=12+18a
12=18a
a=12/18
=4/6=2/3
u=2ms-1
s=24m
t=6s
a=?
s=ut+1/2at²
24=2*6+1/2*a*36
24=12+18a
12=18a
a=12/18
=4/6=2/3
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