Question

a body revolving round in circles calculate distance and displacement for 360 degree 180 degree 90 degree 60 degree and 40 degree

Answer 1

displacement for 360= 0,,,, displacement for 180=equal to diameters,,,, displacement for 90 = let A the initial point and B the final point ,and O Aso center then~= {ao}^{2} + {bo}^{2} = {ab \\}^{2} \\ then ab = \sqrt{ {ao}^{2} + {bo}^{2} }

Answer 2

for 360 distance =circumference and displacement is equal to 0

for 180° distance is equal to half of the circumference and displacement is equal to diameter

for 90° distance is equal to One fourth of the circumference and displacement is equal to under root radius square plus radius square