Question

A body rises vertically up to height of 125 m in 5 s and then comes back at the point of projection. Find: (i) The total distance travelled, (ii) the displacement (iii) the average speed (iv) the average velocity of the body.​

Answer 1

Explanation:

Total distance=250m(125+125)

Total displacement=0(because displacement is length between initial point and final point. Here initial point and final point. So displacement is 0.)

Average speed=Total distance÷total time taken

=250÷10=25meter per second

Average velocity=Total displacement÷total time taken

=0÷10=0

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Answer 2

Explanation:

Solution :

Given :

• S = 125m
• t = 5s

Calculation :

(i) Total distance travelled= S + S = 2S

=> 2 × 125m => 250m.

(ii) Displacement = 0 (since final position is same as initial position).

(iii) Average Speed = Total distance travelled / Total time of journey

=> 2S/2t = 2 × 125m/2 × 5s

=> 250m/10s = 25m/s.

(iv) Average velocity = 0 (since displacement is zero).