A body starting from rest has an acceleration of 5 m/s2. Calculate the distance travelled by it in 4th second
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Answered by
2
v=final point
u=initial point
a=acceleration
t=time
v=u+at (first eq of motion)
v=0+5×4
v=20
u=initial point
a=acceleration
t=time
v=u+at (first eq of motion)
v=0+5×4
v=20
Answered by
0
Hence ur ans. is 10m/s
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