Physics, asked by satishkumarkattiri3, 1 day ago

A body starting from rest is moving with a velocity of 5 m/s and covered a distance of 20 m. Calculate acceleration of the body​

Answers

Answered by SparklingBoy
87

 \large \dag Question :-

A body starting from rest is moving with a velocity of 5 m/s and covered a distance of 20 m. Calculate acceleration of the body.

 \large \dag Answer :-

\red\dashrightarrow\underline{\underline{\sf  \green{Acceleration  \: of \: body  \:  is \:  0.625\: m/s^2 }} }\\

 \large \dag Step by step Explanation :-

Here we have :

Initial Velocity = u = 0 m/s

Final Velocity = v  = 5 m/s

Distance Covered = s = 20 m

Let Acceleration be = a m/s²

 We Have 3rd Equation of Motion as :

\large \bf \red\bigstar \: \: \orange{ \underbrace{ \underline{\blue{v^2-u^2 = 2as}}}}

⏩ Applying 3rd Equation of Motion ;

:\longmapsto \rm  {5}^{2}  - 0 {}^{2}  = 2 \times a \times 20 \\

:\longmapsto \rm 25 - 0 = 40a \\

:\longmapsto \rm 40a = 25 \\

:\longmapsto \rm a  =  \frac{25}{40}  \\

\purple{ \large :\longmapsto  \underline {\boxed{{\bf a = 0.625} }}}

Therefore,

\large\underline{\pink{\underline{\frak{\pmb{\text Acceleration = 0.625 \: m/s^2 }}}}}

Answered by MяMαgıcıαη
33

Answer:

  • Acceleration of body = 0.625 m/

Explanation:

Given information,

A body starting from rest is moving with a velocity of 5 m/s and covered a distance of 20 m. Calculate acceleration of the body.

  • Initial velocity (u) = 0 m/s
  • Final velocity (v) = 5 m/s
  • Distance covered (s) = 20 m

Using 3rd eq of motion,

v² = + 2as

Where,

  • v denotes final velocity
  • u denotes initial velocity
  • a denotes acceleration
  • s denotes distance covered

We have,

  • u = 0 m/s
  • v = 5 m/s
  • s = 20 m
  • a = ?

Putting all values,

➻ 5² = 0² + 2(a)(20)

➻ 5 × 5 = (0 × 0) + (2 × a × 20)

➻ 25 = 0 + (2 × 20 × a)

➻ 25 = 0 + (40 × a)

➻ 25 = 0 + (40a)

➻ 25 = 0 + 40a

➻ 25 = 40a

➻ 40a = 25

➻ a = 25/40

➻ a = 5/8

a = 0.625

  • Hence, acceleration of a body is 0.625 m/s².

Three equations of motion,

  1. v = u + at
  2. s = ut + ½ at²
  3. v² = u² + 2as

Where,

  • v denotes final velocity
  • u denotes initial velocity
  • a denotes acceleration
  • s denotes distance covered
  • t denotes time taken

Some important definitions,

  • Acceleration

Acceleration is the process where velocity changes. Since, velocity is the speed and it has some direction. So, change in velocity is considered as acceleration.

  • Initial velocity

Initial velocity is the velocity of the object before the effect of acceleration.

  • Final velocity

After the effect of acceleration, velocity of the object changes. The new velocity gained by the object is known as final velocity.

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