A body starting from rest is moving with a velocity of 5 m/s and covered a distance of 20 m. Calculate acceleration of the body
Answers
Question :-
A body starting from rest is moving with a velocity of 5 m/s and covered a distance of 20 m. Calculate acceleration of the body.
Answer :-
Step by step Explanation :-
Here we have :
Initial Velocity = u = 0 m/s
Final Velocity = v = 5 m/s
Distance Covered = s = 20 m
Let Acceleration be = a m/s²
❒ We Have 3rd Equation of Motion as :
⏩ Applying 3rd Equation of Motion ;
Therefore,
Answer:
- Acceleration of body = 0.625 m/s²
Explanation:
Given information,
A body starting from rest is moving with a velocity of 5 m/s and covered a distance of 20 m. Calculate acceleration of the body.
- Initial velocity (u) = 0 m/s
- Final velocity (v) = 5 m/s
- Distance covered (s) = 20 m
Using 3rd eqⁿ of motion,
✪ v² = u² + 2as ✪
Where,
- v denotes final velocity
- u denotes initial velocity
- a denotes acceleration
- s denotes distance covered
We have,
- u = 0 m/s
- v = 5 m/s
- s = 20 m
- a = ?
Putting all values,
➻ 5² = 0² + 2(a)(20)
➻ 5 × 5 = (0 × 0) + (2 × a × 20)
➻ 25 = 0 + (2 × 20 × a)
➻ 25 = 0 + (40 × a)
➻ 25 = 0 + (40a)
➻ 25 = 0 + 40a
➻ 25 = 40a
➻ 40a = 25
➻ a = 25/40
➻ a = 5/8
➻ a = 0.625
- Hence, acceleration of a body is 0.625 m/s².
Three equations of motion,
- v = u + at
- s = ut + ½ at²
- v² = u² + 2as
Where,
- v denotes final velocity
- u denotes initial velocity
- a denotes acceleration
- s denotes distance covered
- t denotes time taken
Some important definitions,
- Acceleration
Acceleration is the process where velocity changes. Since, velocity is the speed and it has some direction. So, change in velocity is considered as acceleration.
- Initial velocity
Initial velocity is the velocity of the object before the effect of acceleration.
- Final velocity
After the effect of acceleration, velocity of the object changes. The new velocity gained by the object is known as final velocity.
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