Physics, asked by hiyathakkar1, 1 year ago

A body starts from rest and moves with a uniform acceleration of 2 m s/ 2 - until it travels a distance of 625 m. Find its velocity.

Answers

Answered by BrainlyConqueror0901
44

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{Final\:velocity=50\:m/s}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{\underline \bold{Given :}} \\  \tt:  \implies Acceleration(a) = 2 \: m/s^{2} \\  \\ \tt:   \implies Distance(s) = 625\: m \\  \\   \red{\underline \bold{To \: Find:}} \\  \tt:  \implies Final\:velocity(v) = ?

• According to given question :

 \tt \circ \: Initial \: speed = 0\: m/s \\  \\  \tt \circ \: Distance= 625 \\\\ \tt\circ\:Acceleration=2\:m/s^{2} \\  \\  \bold{As \: we \: know \: that} \\  \tt:  \implies v^{2} = u^{2} + 2as \\  \\ \tt:  \implies v^{2} =0^{2}+2\times 2\times 625 \\  \\ \tt:  \implies v^{2} =4\times 625 \\  \\ \tt:  \implies  v^{2}=2500   \\  \\ \tt:  \implies v= \sqrt{2500} \\  \\  \green{\tt:  \implies v = 50\:m/s } \\  \\   \green{\tt \therefore Velocity \: after\:travelling\:625\:m \: is \:  50\:  {m/s} } \\  \\  \blue{ \bold{Some \: related \: formula}} \\  \orange{ \tt \circ \: v  =  {u}  +at} \\  \\ \orange{ \tt \circ \:  s  =  ut+  \frac{1}{2}a {t}^{2}  }

Answered by ғɪɴɴвαłσℜ
36

Aɴꜱᴡᴇʀ

v = 50 m/s

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Gɪᴠᴇɴ

 \sf{} \bigstar \:initial \: velocity \: (u) = 0 \: m/s \\  \\ \sf{}\bigstar distance = 625 \: m \\  \\ \sf \bigstar acceleration = 2m/ {s}^{2}

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ᴛᴏ ꜰɪɴᴅ

The velocity of the body

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Sᴛᴇᴘꜱ

As we already know the initial velocity of the body, the distance travelled and the acceleration of the body , the formula that fits the given data is obviously

 \large \orange{ \tt{} {v}^{2} -  {u}^{2}  = 2as }

Where,

  • v = is the final velocity

  • u is the initial velocity

  • a is the accelerataion

  • and s is the distance

Calculation:-

\tt{} \leadsto{} {v}^{2}  =  {u}^{2}  + 2as \\   \\ \tt{} \leadsto  {v}^{2}  =  {0}^{2}  + 2(2)(625) \\  \\  \tt{} \leadsto {v}^{2}  = 2500 \\  \\  \tt{} \leadsto  v =  \sqrt{2500}  \\  \\ \large\tt{} \purple{ \dashrightarrow{}v = 50 \: m/s}

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Some important formulas :-

  • v = u+at

  • \sf{}s =ut +\frac{1}{2} a{t}^{2}
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