a body starts from rest and moves with a uniform acceleration of 4 m per second square for 6 seconds and then it moves with a constant velocity for 5 seconds later it slows down and comes to rest in 8 seconds draw the velocity time graph for the motion of the body and answer the following questions apart what is the maximum velocity attained by the body be part what is the distance travelled during this period of expiration C part what is the distance travelled when the body was moving with constant velocity the parts what is the retardation of the body while slowing down Ispat what is the distance travelled by retarding Ispat what is the total distance travelled
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v max=24m/s
distance travelled in accelerating part=59.5m
distance travelled with constant velocity =24*5=120m
retardation will be u=at
a=8m/s^2
distance travelled during retardation = 79.3 m
total distance travelled =59.5+120+79.3=258.8m
distance travelled in accelerating part=59.5m
distance travelled with constant velocity =24*5=120m
retardation will be u=at
a=8m/s^2
distance travelled during retardation = 79.3 m
total distance travelled =59.5+120+79.3=258.8m
abhaypawar:
thanku for the solution
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