Question

A body starts from rest and moves with
constant acceleration. It travels a distance
s1 in the first 10 s and distance s2 in next
10 s. Find the relation between s1 and s2.​

Answer 1

Answer:

s1 : s2 = 1 : 3

Explanation:

u = 0

t = 10

$\boxed{s = ut + \dfrac{1}{2}a{t}^{2}}$

s1 = 0(10) + 1/2 a(10)²

s1 = 100a/2

s1 = 50a

Now,

u = 0, t = 10+10 = 20sec

s = 0 + 1/2 a(20)²

s = 400a/2

s = 200a

_____________________________

s2 = s - s1

s2 = 200a - 50a

s2 = 150a

___________________________

s1/s2 = 50a/150a = 1/3

s1 : s2 = 1:3

Answer 2

Hey mate here is your answer

S2 = 3S1

❤❤

Hope the above attachment will help you

If yes then plz mark it as BRAINLIEST ‼

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