Question

Find the acceleration of the moon with respect to the earth from the following data: Distance between the earth and the moon = 3.85 x 10^5 km and the time taken by the moon to complete one revolution around the earth =27.3 days.?

Answer 1

Given conditions ⇒

Distance between earth and moon = 3.85 × 10⁵ km. = 3.85 × 10⁸ m.

Time taken = 27.3 days = 655.2 hrs. = 2358720 seconds.

∴ Distance traveled by the moon in one revolution = 2πr

= 2 × 3.14 ×  3.85 × 10⁸

= 24.2 ×  10⁸ m.

Now,

v = distance/time.

= 24.2 ×  10⁸/2358720

= 1025.98 m/s.  

Now, Acceleration = v²/r

= (1025.98)²/3.85 × 10⁸

= 2.73 × 10⁻³ m/s².

Hope it helps.

Answer 2

Answer:

2.73×10^(-3)m/s^2

Explanation:

=> w= 2¶/t

=> centripetal acceleration=Rw^2

(note: w=omega)