Question

A body starts from rest and travels with uniform acceleration on a straight line. If its velocity after making a displacement of 32 m is 8 m/s then it's acceleration is
A. 1 m/s²
b. 2 m/s²
c. 3 m/s²
d. 4 m/s²​

Answer 1

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A body starts from rest and travels with uniform acceleration on a straight line. If its velocity after making a displacement of 32 m is 8 m/s then it's acceleration is

☑ a. 1 m/s²

b. 2 m/s²

c. 3 m/s²

d. 4 m/s²

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Explanation :-

➝ Given :-

• Initial velocity, u = 0
• Final velocity, v = 8m/s
• Displacement, S = 32m

➝ To find :-

acceleration of body..

➝ Solution :-

As the body moves with uniform acceleration we have to use the third equation of motion

$\longrightarrow \sf {v}^{2} - {u}^{2} = 2as$

$\longrightarrow \sf {80}^{2} - {0}^{2} = 2a(32)$

$\longrightarrow \sf 64 = 64a$

$\longrightarrow\sf a = \cancel\frac{64}{64}$

$\longrightarrow \boxed{ \sf a = 1 {ms}^{ - 2}}$

Hence, acceleration of body is 1m/s².

Thus, Option (a) is right

Answer 2

Given:

A body starts from rest and travels with uniform acceleration on a straight line.

To find:

Acceleration of body?

Solution:

Final velocity after travelling 32 metres = 8 m/s.

• Let's assume constant acceleration to be 'a'.

• Also, the body starts from rest.

Applying Equation of Kinematics:

${v}^{2} = {u}^{2} + 2as$

$\implies \: {8}^{2} = {0}^{2} + 2(a)32$

$\implies \: {8}^{2} =64a$

$\implies \: 64a = 64$

$\implies \: a = 1 m { s }^{ - 2}$

So, acceleration of object is 1 m/s².