Question

A body starts from rest and travels with uniform acceleration of 2 m/s2 . If its velocity is v after making a displacement of 9 m, then v is

1 point
A body starts from rest and travels with uniform acceleration of 2 m/s2 . If its velocity is v after making a displacement of 9 m, then v is






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Answer 1

Answer:

Kinematics

Explanation:

★ Given ;

» Acceleration ( a ) = 2 m / s²

» displacement ( s ) = 9 m

» initial velocity ( u ) = 0 ( at rest )

★ Final velocity ( v ) = ?? ★

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★ From 3rd equation of motion

V² - U² = 2 × a × s

» V² - ( 0 )² = 2 × 2 × 9

» V² = 36

★ Final velocity ( v ) = 6 m / s . ★

Answer 2

Given:

A body starts from rest and travels with uniform acceleration of 2 m/s². Velocity v is reached after travelling 9 m .

To find:

Value of v ?

Calculation:

• Initial velocity is zero , as body starts from rest.

Applying EQUATIONS OF KINEMATICS:

$\rm \: {v}^{2} = {u}^{2} + 2as$

$\rm \implies {v}^{2} = {(0)}^{2} + 2(2)(9)$

$\rm \implies {v}^{2} = 0 + 36$

$\rm \implies {v}^{2} = 36$

$\rm \implies v = \sqrt{36}$

$\rm \implies v = 6 \: m {s}^{ - 1}$

So, final velocity is 6 m/s