Question

A body starts from rest at point A and travels upto point B with constant acceleration of 10m/s^2 in 4 secs. then from point B it travels to point C with constant acceleration of 20m/s^2 in 8 secs

FIND 1. velocity of the body at point B

2. velocity of the body at point C

3. total distance travelled by the body?

Answer 1

Answer:

Let s is the displacement of the body. The formula that relates the acceleration, displacement and the velocity is given by :

The body is at rest initially, u = 0. Put t = 2 sec in above formula as :

So, when a body starts from rest, the acceleration of the body after 2 seconds is  half of its displacement. Hence, this is the required solution.

Read more on Brainly.in - https://brainly.in/question/343020#readmore

Explanation:

Answer 2

Answer:

velocity at the B will be 400 m/s

Velocity of the body at the C will be 400 + 400*8 = 3600 m/s

total distance traveled is = 16800 m

Explanation: