Question

A body starts moving from a state of rest with an acceleration of 0.5 m/s?.
After covering a distance of 250m the velocity of the body will be:
(a) 12.5 m/s
(b) 15.8 m/s (c) 18.7 m/s (d) None of these
explain detail​

Answer 1

FINAL ANSWER:-

(b) 15.8 m/s

GIVEN:-

$(u)=0m/s$

$(a)=0.5m/s$

$(s)=250m$

TO FIND:-

After covering a distance of 250m the velocity of the body

FORMULA USED:-

$v^{2}=u^{2}+2as$

SOLUTION:-

body starts moving from a state of rest $(u)=0m/s$

it's acceleration $(a)=0.5m/s$

distance covered by the body $(s)=250m$

here,

$(u)=0m/s$

$(a)=0.5m/s$

$(s)=250m$

by using $v^{2}=u^{2}+2as$

$v^{2}=0^{2}+2*0.5*250$ [← putted vales in equation]

$v^{2}=0+250\\v{2}=250\\v= \sqrt{250}\\v=15.8m/s$

hence , velocity of the body will be $15.8m/s$

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Note:- it's not necessary that you only use the formula/ME that i did answer can be obtained by more than 1 formula

Answer 2

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