Question

A body thrown upwards with a velocity of 50 m/s .Calculate the height it reaches (g=10m/s2 )​

Answer 1

Figure regards question:

$\setlength{\unitlength}{1mm}\begin{picture}(7,2)\thicklines\multiput(7,2)(1,0){55}{\line(3,4){2}}\multiput(35,7)(0,4){12}{\line(0,1){0.5}}\put(10.5,6){\line(3,0){50}}\put(35,60){\circle*{12}}\put(37,7){\large\sf{u = 50 m/s}}\put(37,55){\large\sf{v = 0 m/s}}\put(21,61){\large\textsf{\textbf{Body}}}\put(43,40){\line(0, - 4){28}}\put(43,35){\vector(0,4){18}} {\pmb{\sf{BrainlyButterfliee}}}\put(24, - 3){\large\sf{ \sf g = -10 m/s^2 }}\put(48,30){\large\sf{H = ?}}\end{picture}$

• You can see the diagram from web or attachment too! :)

Provided that:

• Final velocity = 0 mps
• Initial velocity = 50 mps
• g = - 10 mps sq.

Don't be confused!

• Final velocity cames as zero because the body is thrown upwards and we know that final velocity is zero if an object will thrown vertically upward.

• We are taking value of g as negative because the object is thrown upwards.

To calculate:

• Height

Solution:

• Height = 125 m

Using concept:

• Third equation of motion

Using formula:

• v² - u² = 2gs

Where, v denotes final velocity, u denotes initial velocity, g denotes acceleration due to gravity and s denotes displacement or distance or height.

Required solution:

»»» v² - u² = 2gs

»»» (0)² - (50)² = 2(-10)(s)

»»» 0 - 2500 = -20s

»»» -2500 = -20s

»»» 2500 = 20s

»»» 2500/20 = s

»»» 250/2 = s

»»» 125 = s

»»» s = 125 m

»»» Distance = 125 metres

Know more:

$\begin{gathered}\boxed{\begin{array}{c}\\ {\pmb{\sf{Three \: equation \: of \: motion}}} \\ \\ \sf \star \: v \: = u \: + at \\ \\ \sf \star \: s \: = ut + \: \dfrac{1}{2} \: at^2 \\ \\ \sf \star \: v^2 - u^2 \: = 2as\end{array}}\end{gathered}$