A body traveling with uniform acceleration crosses two points A and B with velocities 20m/s and 30m/s respectively. The speed of the body at midpoint of A and B is
Answers
Answered by
7
we can write v₂ - u₂ = 2as = 900 - 400 = 500
∴ as = 250 --- (1)
at s/2 if speed is w: w₂ - u₂ = 2a(s/2)
∴ w₂ = u₂ + as = 400 + 250, using (1).
⇒ w = sqrt(650) = 25.5 m/s(approx)
∴ as = 250 --- (1)
at s/2 if speed is w: w₂ - u₂ = 2a(s/2)
∴ w₂ = u₂ + as = 400 + 250, using (1).
⇒ w = sqrt(650) = 25.5 m/s(approx)
Answered by
4
Velocity is 25 because according to formula of acceleration (20 + 30)/2 = 25
Similar questions
English,
8 months ago
CBSE BOARD XII,
8 months ago
Physics,
1 year ago
Chemistry,
1 year ago
Math,
1 year ago