Question

A person starts from his home on a straight road in his car at a speed of 50 metre per second for half an hour then the Fuel in his finishes. So he stops walks to petrol pump and gets back to car in 20 min. Then he again starts moving in initial direction of motion with same speed of 50 metre per second. What is the average velocity of the man in 1 hr after he started from his home?

Answer 1

first speed=50 m/sec

second speed=20 m/sec

third speed=50m/sec

so,the average is equal to


SUM OF OBSERVATIONS /
TOTAL NO. OF OBSERVATIONS

= 50+20+50/3

=120/3=40 m/sec..


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Answer 2

The average velocity of the man is 120 km.

Explanation:

In first half hour distance covered = 50 x 30 x 60 = 90 km

In next 20 minutes the displacement will be zero because it return back to the same position.

Distance covered in next 10 minutes = 50  x 10 x 60 = 30 km

Total distance or displacement covered = 90 km + 30 km = 120 km

$\text{Average velocity} = \frac{120}{1} \\\text{Average velocity} = 120 km$

Learn More:

What is average velocity ?

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