Question

A body travels a distance of 8m from A to B ,then moves a distance of 6m at right angles to AB. What is the total distance travelled? Find the magnitude of resultant displacement?​

Answer 1

Answer:

Total distance is sum of the distance AB & BC where C is final point perpendicular to AB which is 8+6=14.

While displacement is the shortest distance AC which can be found using Pythagoras theorem as body moves from A to B,then moves a distance of 6m at right angles to AB. Then we get AC=(8^2+6^2)^1/2 i.e. (64+36)^1/2= 100^1/2 = 10.

Answer 2

Total distance is sum of the distance AB & BC where C is final point perpendicular to AB which is 8+6=14.

While displacement is the shortest distance AC which can be found using Pythagoras theorem as body moves from A to B,then moves a distance of 6m at right angles to AB. Then we get AC=(8^2+6^2)^1/2 i.e. (64+36)^1/2= 100^1/2 = 10.

Hello, Madam Mis.Padma i found it.