Physics, asked by verma3528, 1 year ago

A body travels half od its total distance in last sec of its fall fro rest the time of fall is

Answers

Answered by Anonymous
0

hey

gd morning

here is your answer

suppose the body travelled total t second and the height is h then we have

1/2gt^2 = h

and

1/2 g(t-1) ^ 2=h/2=1/4 gt^2

=>g(t^2 + 1 - 2t) = 1/2gt^2

=>1/ 2gt ^2- 2gt+g=0

=> 3.41

As the body travelled more than 1 s so answer is 3.41s


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