Question

a body travels in a semicircular path of radius 10m starting its motion from point a to b calculate the distance and displacement

Answer 1

Distance = Semicircular path
= πr
= 3.14 × 10 m
= 31.4 m

Displacement = Shortest Distance between initial and final position
= Diameter of semicircle
= 2r
= 2 × 10 m
= 20 m

Answer 2

distance.will be half of the circumference of circle
so distance travelled=π*radius=3.14*10=31.4m
displacement will be equal to diameter so
it is equal to 2×10=20 m