Question

a body was projected by an angle of 30 degree to the horizontal at intial velocity. after 4 seconds its velocity in the vertical dimension was $frac{1}{4}$ the intial velocity

a)7.5 m/s
b)40 m/s
c)160 m/s
d)80 m/s

Answer 1

the answer is in the image attached..

Answer 2

The correct option is A.

The correct option is A.Given,

The correct option is A.Given,Speed=30m/s,t=1.5s,g=10m/s2

The correct option is A.Given,Speed=30m/s,t=1.5s,g=10m/s2So, the velocity along an x-axis

The correct option is A.Given,Speed=30m/s,t=1.5s,g=10m/s2So, the velocity along an x-axisvx=ucosθ

The correct option is A.Given,Speed=30m/s,t=1.5s,g=10m/s2So, the velocity along an x-axisvx=ucosθ30×cos300

The correct option is A.Given,Speed=30m/s,t=1.5s,g=10m/s2So, the velocity along an x-axisvx=ucosθ30×cos300=30×23

The correct option is A.Given,Speed=30m/s,t=1.5s,g=10m/s2So, the velocity along an x-axisvx=ucosθ30×cos300=30×23=153m/s

The correct option is A.Given,Speed=30m/s,t=1.5s,g=10m/s2So, the velocity along an x-axisvx=ucosθ30×cos300=30×23=153m/sAgain,

The correct option is A.Given,Speed=30m/s,t=1.5s,g=10m/s2So, the velocity along an x-axisvx=ucosθ30×cos300=30×23=153m/sAgain,Vy=usin300−gt

The correct option is A.Given,Speed=30m/s,t=1.5s,g=10m/s2So, the velocity along an x-axisvx=ucosθ30×cos300=30×23=153m/sAgain,Vy=usin300−gt30×21−gt

The correct option is A.Given,Speed=30m/s,t=1.5s,g=10m/s2So, the velocity along an x-axisvx=ucosθ30×cos300=30×23=153m/sAgain,Vy=usin300−gt30×21−gt15−10t

The correct option is A.Given,Speed=30m/s,t=1.5s,g=10m/s2So, the velocity along an x-axisvx=ucosθ30×cos300=30×23=153m/sAgain,Vy=usin300−gt30×21−gt15−10tNow After t=1.5s

The correct option is A.Given,Speed=30m/s,t=1.5s,g=10m/s2So, the velocity along an x-axisvx=ucosθ30×cos300=30×23=153m/sAgain,Vy=usin300−gt30×21−gt15−10tNow After t=1.5svx=153m/s

The correct option is A.Given,Speed=30m/s,t=1.5s,g=10m/s2So, the velocity along an x-axisvx=ucosθ30×cos300=30×23=153m/sAgain,Vy=usin300−gt30×21−gt15−10tNow After t=1.5svx=153m/svy15−10×1.5=0

The correct option is A.Given,Speed=30m/s,t=1.5s,g=10m/s2So, the velocity along an x-axisvx=ucosθ30×cos300=30×23=153m/sAgain,Vy=usin300−gt30×21−gt15−10tNow After t=1.5svx=153m/svy15−10×1.5=0So 153m/salong x-axis  y making n angle zero.