Question

When a steady force of 75 N is applied on a body at rest for 20 seconds, it attains a speed of 30 ms
What is the steady retarding force required to stop the body in 5 seconds?
(300 N)​

Answer 1

Explanation:

75/m=30/20

m=50kg so

regarding force=

v=0,u=30 so a= 30/5=6m/s^2

so force will be

f=m a

f=50kg.6= 300n