Question

A body weight 200N on the surface of the earth Its weight at depth equal to half of the radius of earth is

Answer 1

800N should be the answer

Answer 2

Answer:

Weight at depth is 100 N

Explanation:

Weight of a body on the surface of earth, W = 200 N

Weight is body is given by :

W = m g

g is the acceleration due to gravity on earth, g = 10 m/s²

So, m = 20 kg

Weight of an object at the depth :

$g_d=g(1-\dfrac{d}{R})$

d is the depth

R is the radius of earth

We have to find the weight of a body at depth equal to the half the radius of earth i.e. d = R/2

So, $g_d=g(1-\dfrac{R/2}{R})$  

$g_d=\dfrac{g}{2}$

So,  $g_d=5\ m/s^2$    

Therefore, the weight of the body at the depth is equal to, $W=m\times g_d$  

$W=20\times 5$    

W = 100 N  

Hence, the weight at depth is 100 N