Question

a body weight 72 N on the surface of the earth . calculate gravitational force on it due to the earth at a height equal to half of the earth

Answer 1

Answer:

According to Newton's gravitational law,

here W is the weight of body on he surface of earth, h is the height of body from the surface of earth, r is the radius of earth.

here, weight to body , W = mg = 72N on the surface of earth. we have to find out weight of body at a height equal to half the radius of the earth above the earth's surface.

so, h = r/2

so, weight of body =

= 72/(1 + 1/2)² = 72/(3/2)² = 72 × 4/9 = 32N

Answer 2

Answer:

here

Explanation:

the body weight is equal to =72N

then mass =72/10

as w=mg

mass=7.2kg

then the gravitational force at height H=R/2

where R is radius of earth

so the total distance between them is

R+R/2=3R/2

if at surface of earth gravity force =72=GmM/R^2

so at height =GmM/R^2*4/9

72*4/9=8*4=32N