Question

A body with an initial velocity of 1/3 moves with an acceleration of 2 ms 2, then the distance travelled in the 4
thsecond is​

Answer 1

TOPIC :- Motion in one dimension

$\maltese\:\underline{\textsf{\textbf{Correct Question :}}}\:\maltese$

A body with an initial velocity of 3 m/s moves with an acceleration of 2 m/s², then the distance travelled in the 4th second is?

$\maltese\:\underline{\textsf{\textbf{AnsWer :}}}\:\maltese$

Displacement of a particle in nth second is calculated by the given below formula :

$\longrightarrow\:\:\sf S_n = u + \dfrac{a}{2} (2n - 1)$

We're provided with initial velocity (u) 3 m/s and Acceleration (a) 2 m/s² . Substitue this given values in above formula :

$\longrightarrow\:\:\sf S_n = 3 + \dfrac{2}{2} (2 |4| - 1)$

$\longrightarrow\:\:\sf S_n = 3 + (8- 1)$

$\longrightarrow\:\:\sf S_n = 3 + 7$

$\longrightarrow\:\: \underline{ \boxed{\sf S_n = 10 \: m}}$

$\therefore\:\underline{\textsf{Distance travelled in 4 ^{\text{th}} second is \textbf{10 m}}}.$