Question

A body with an initial velocity of 18 kmh–1 accelerates uniformly at the rate of 9 cms–2 cover a distance
of 200 m. Calculate :
(i) the acceleration in ms–2

Answer 1

Answer:

Given, initial velocity u=18kmh

−1

=

60×60

18000m

=5ms

−1

Acceleration a=0.09ms

−2

and distance s = 200 m

From equation of motion v

2

=u

2

+2as,

We get, v=

5

2

+2×0.09×200

m/s=7.81m/s

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