a body with uniform acceleration covers 76 m in the 5th sec and 116 m in the 10th sec.Find the distance travelled in the 15th sec.what is the distance travelled in next 5 seconds.Please explain in detail
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Answered by
6
∆•••••••••••••••••••••••∆
10sec. 15sec
116m. ?
take equality:-
(10:15) =(116 : ?)
(10/15)=(116 / ?)
? = 174m
so,distance travel in the 15th sec is 174m.
similar for next 5sec.
or next 20th sec
∆••••••••••••••••••••••••∆
15sec. 20sec
174m. ?
10sec. 15sec
116m. ?
take equality:-
(10:15) =(116 : ?)
(10/15)=(116 / ?)
? = 174m
so,distance travel in the 15th sec is 174m.
similar for next 5sec.
or next 20th sec
∆••••••••••••••••••••••••∆
15sec. 20sec
174m. ?
rati212:
actually the given answer is for 15th sec is 156 m and for next 5 seconds is 700 m
can someone please help me with the answer
Answered by
9
Explanation:For answering , the 4th equation of motion is to be used.
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