A bomb is dropped from an aeroplane when it is directly above target from height 1000 m, aeroplane is moving with velocity 500 kmph find how much distance will bomb mIss target ?
Answers
Answered by
153
Time taken to reach the ground = √(2H/g)
= √(2 × 1000 / 10)
= √(200)
= 10√2 seconds
Distance = Velocity × Time
= (500 × 5/18 m/s) × 10√2 s
= 1964.1 m
= 1.964 km
The bomb wil miss the target by distance of 1.964 km
= √(2 × 1000 / 10)
= √(200)
= 10√2 seconds
Distance = Velocity × Time
= (500 × 5/18 m/s) × 10√2 s
= 1964.1 m
= 1.964 km
The bomb wil miss the target by distance of 1.964 km
Answered by
18
------->500 km/hr
|-> -|-
| |
| 1000m
|__|________. <--- bomb
|------R------------|
R= u x √2h/g
u is given in km/hr,
1km/hr = 1 x 5/18 m/s
500km/hr = 500 x 5/18
h=1000m
g unless given in the question has to be taken as 9.8m/s2
substituting the values,
R = 500 x 5/18 x √2 x 1000/9.8
R= 500 x 5/18 x 100/7
R = 1984.12m
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