Question

A book of mass 20g is a placed on a table. Find the thrust exerted by the book on the table. [ take acceleration due to gravity as 10 m /ssquare
The foot of the elephant has an area of 2200kg find the pressure exerted by the elephant on the ground [g=m/s2 ​

Answer 1

Answer:

Step-by-step explanation:

Thrust exerted is the force exerted,

A book exerts a force equal to its gravitational weight on the table on which it is placed through the surface of contact.

 Thrust Force = weight = mass * acceleration due to gravity

Let acceleration due to gravity = g = 10 m/s²

  thrust = 0.020 kg * 10 m/s² = 0.200 Newtons.

 Mass of the given elephant = 2,200 kg.

 Weight of the elephant = mass * gravity = 2,200 * 10 = 22,000 Newtons.

 Area of the base of the foot of the given elephant = not given.

 Let us assume it is a circle of radius about 15 cm. So area will be about 3.14* 15² cm² = 707 cm² = 0.0707 m²

 There are four feet of the elephant. So the weight is distributed equally among the feet. - Assume so.

 Pressure = thrust force or weight / area of the base of the foot.

                 = 22,000/ (4 * 0.0707) = 77,793 Pascal or N/m²

Answer 2

[g=m/s2]

Step-by-step explanation:

mass of book (m)=20

gram=201000 kg =150 k

thrust by , the book is 0.2n

therefore, the trust acting on the table .

=[g =m/s2