Question

A box contain 100 cards marked with numbers 1 to 100. If one card is drawn from the box, find the probability that it bears (i) single digit number, (ii) two-digit numbers (ii) three-digit number (iv) a number divisible by 8 (v) a multiple of 9, (vi) a multiple of 5.

Answer 1

Given
Total Number of Cards = 100
Number of Single Digit Cards = 9
Number of Two Digit Cards = 90
Number of Three Digit Cards = 1
Numbers of Cards divisible by 8 = 12
Numbers of Cards multiple of 9 = 11
Numbers of Cards multiple of 5 = 20
Probability Of (i) = 9/100
Probability of (ii) = 90/100
Probability of (iii) = 1/100
Probability of (iv) = 12/100
Probability of (v) = 11/100
Probability of (vi) = 20/100