Question

A box contains 15 transistors, 5 of which are defective An inspector takes out one transistor at random,

Answer 1

complete the question pla

Answer 2

Hello

Your question is not complete

But your question can have two possibilities

1.
Find the probability of the inspector taking the defective transistors

Answer

N(s)= 15
N(e)= 5

P(e)= n(e)/n(s)

P(e)= 5/15

P(e)= 1/3

2.
Find the probability of the inspector taking the non defective transistors

Answer

N(s)= 15
N(e)= 10

P(e)= n(e)/n(s)

P(e)= 10/15

P(e)= 2/3

That’s it!!!!!

Thank you
Hope it helps

Next time while posting question try to post in full form