Question

A box contains 4 tennis ball, 6 season and 8 dues balls. 3 balls are randomly drawn from the

box. What is the probability that the balls are different?
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Answer 1

Answer:

4/17

Step-by-step explanation:

Given A box contains 4 tennis ball, 6 season and 8 dues balls. 3 balls are randomly drawn from the  box. What is the probability that the balls are different?

We know that probability = favourable outcomes / total number of outcomes

   Assuming that balls are different, there are 18 balls.

Now 3 balls can be chosen in 18 C 3 ways

 = 18 ! / 3! X 15 !  

= 18 x 17 x 16 / 3 x 2 x 1

  = 4896 / 6

 = 816

Now favourable outcomes will be 1 tennis ball, 1 season ball , 1 dues ball

   = 4 x 6 x 8  

 = 192

So probability will be 192 / 816 = 4/17

Answer 2

Answer:

2/51

Step-by-step explanation:

A box contains 4 tennis ball, 6 season and 8 dues balls. 3 balls are randomly drawn from the box. What is the probability that the balls are different?

Tennis Balls = 4

Season Balls = 6

Dues Balls = 8

Total Balls = 4 + 6 + 8 = 18

Total number of ways 3 balls can be drawn

18 * 17 * 16 = 4896   ways

If three balls are different then they can be selected in

4 * 6 * 8  = 192   ways

Probability =  192/4896   =  2/51