Question

a box contains 7 red balls 8 green balls and 5 white balls a ball is drawn at random from the box find the probablity that the ball is ]

a) white

b) neither red nor white

Answer 1

total balls=7+8+5=20
a)PE=5/20=1/4
b)PE=8/20=2/5

Answer 2

ACCORDING TO UR QUESTION,

A BOX CONTAINS ,

RED BALLS = 7

GREEN BALLS = 8

WHITE BALLS = 5

THE PROBABILITY OF FINDING THE WHITE BALL IS

       N{S} = 7+8+5=20

      N(E) = 5

N[S}/N{E} = 5/20 =1/4

THE PROBABILITY OF FINDING WHITE BALL IS 1/4

AND THE PROBABILITY OF FINDING NEITHER RED OR WHITE IS

N{S}=7+8+5=20

N{E} = (RED + WHITE} = 7+5 = 12

N{S} / N{E} = 12/20 = 3/5

THE PROBABILITY OF FINDING NEITHER RED OR WHITE IS 3/5

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         HOPE MY ANSWER WILL HELP U

THANK Q FOR ASKING THIS QUESTION...........