A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random, find the probability that it bears (i) a 2 digit number. (ii) a perfect square. (iii) a number divisible by 5
Answers
Answered by
286
1. P=81/90
=9/10
2. P= 9/90
=1/10
3.P= 18/90
=2/15
=9/10
2. P= 9/90
=1/10
3.P= 18/90
=2/15
Answered by
162
Hey Mate,here is Ur answer.
we know that the total number of discs=90
i) Let A be the probability getting a 2 digit number
therefore
P(A) = 81/90 = 9/10
ii) Let B be the probability of getting a square number
therefore,
P(B) = 9/90 = 1/10
Hope it will help......
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