Question

A box contains numbers from 1 to 100. What is the probability of getting a number which is divisible by 5. ​

Answer 1

Given :

• A box contains numbers from 1 to 100 .

To Find :

• Probability of getting a number which is divisible by 5 .

Solution :

$\longmapsto\tt{Total\:Outcomes=100}$

$\longmapsto\tt{Favourable\:Outcomes=20}$

5 , 10 , 15 , 20 , 25 , 30 , 35 , 40 , 45 , 50 , 55 , 60 , 65 , 70 , 75 , 80 , 85 ,90 , 95 , 100

Using Formula :

$\longmapsto\tt\boxed{Probability=\dfrac{No\:of\:Fav.\:Outcomes}{Total\:No.\:of\:Outcomes}}$

Putting Values :

$\longmapsto\tt{\cancel\dfrac{20}{100}}$

$\longmapsto\tt\bf{\dfrac{1}{5}}$

So , The Probability of getting a number which is divisible by 5 is 1/5 .

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Probability :

It is defined as chances of occuring or happening of an event.

• Probability of an event can never be negative.
• Probability of an event always lies between 0 and 1.

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Answer 2

Given :-

A box contains numbers from 1 to 100

To Find :-

What is the probability of getting a number which is divisible by 5. ​

Solution :-

At first in the we need to find the total number divisible by 5

Number divisible by 5 = 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100

Therefore, there are 20 favourable outcomes

We know that

P = F/T

P = Probability

F = Favourable outcomes

T = Total outcomes

P = 20/100

P = 2/10

P = 1/5

Therefore

Probability of getting a number which is divisible by 5 is 1/5 or 20%